1、3π/4=135°,135°=45°+90°,cos(a+b)=cos a cos b -sin a sin b
2、cos135°=cos(45°+90°)=cos 45° cos 90° -sin 45° sin 90°
cos 45°=√2/2
sin 45° =√2/2
cos 90°= 0
sin 90° = 1
3、cos135°=cos(45°+90°)=cos 45° cos 90° -sin 45° sin 90°
=√2/2* 0 - √2/2*1
=-√2/2
时间:2026-02-13 04:22:40
1、3π/4=135°,135°=45°+90°,cos(a+b)=cos a cos b -sin a sin b
2、cos135°=cos(45°+90°)=cos 45° cos 90° -sin 45° sin 90°
cos 45°=√2/2
sin 45° =√2/2
cos 90°= 0
sin 90° = 1
3、cos135°=cos(45°+90°)=cos 45° cos 90° -sin 45° sin 90°
=√2/2* 0 - √2/2*1
=-√2/2